http://misha-b.livejournal.com/ (
misha-b.livejournal.com
) wrote
in
shvarz
2011-04-12 05:31 pm (UTC)
Re: вряд ли
Для суммы квадратов?
1^1+2^2 + ...+n^2 = n(n+1)(2n+1)/6
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Re: вряд ли
1^1+2^2 + ...+n^2 = n(n+1)(2n+1)/6